求y=sin대2x的导函数

2025-02-02 15:00:25
推荐回答(1个)
回答1:

令f(x)=y=sin³2x
f'(x)=3sin²2x·(sin2x)'
=3sin²2x·cos2x·(2x)'
=3sin²2x·cos2x·2
=3·(2sin2xcos2x)·sin2x
=3sin4xsin2x
=3·½·[cos(4x-2x)-cos(4x+2x)]
=(3/2)cos2x -(3/2)cos6x
函数的导函数为(3/2)cos2x -(3/2)cos6x