一道初一的数学题5,急急急!!!求过程!!!

2024-12-28 03:48:33
推荐回答(2个)
回答1:

4x-3y-6z=0 (1)
x+2y-7z=0 (2)
(1)*2+(2)*3
8x-12z+3x-21z=0
11x=33z
x=3z
(1)-(2)*4
-3y-6z-8y+28z=0
-11y=-22z
y=2z

(2xy+3yz-6zx)/(x^2+5y^2+7z^2)
=(6z^2+6z^2-18z^2)/(9z^2+20z^2+7z^2)
=-6z^2/36z^2
=-1/6

回答2:

确定题目正确么