钟表上12时15分时,时针和分针的夹角是多少度

需要详细的计算过程
2024-11-27 11:43:06
推荐回答(5个)
回答1:

首先我们要明确以下事实
1、表盘一圈有60格(分的一格),是360度,所以一格是6度
2、分针走一格(即一分钟),时针走十二分之一格
所以,分针转过6度,时针转过0.5度

12点整时分针时针重合向上,15分钟后
分针转过15×6度=90度
时针转过15×0.5度=7.5度
两针夹角=90-7.5=82.5(度)

答:……

回答2:

12时15分,时针转过整个60分钟的4分之1一个大格(如12到1)=360÷12=30度4分之1=30×1/4=7.5度如果时针正对着12,分针对着3,是90度90度-7.5度=82.5度,即12时15分,时针和分针的夹角是82.5度

回答3:

15*360/60-15/60*360/12=92.5

回答4:

82.5度
如果时针不动
夹角90度
时针一个小时运动360/12度
也就是30度
15分钟
也就是1/4小时
时针运动30/4度
也就是7.5度
那么夹角就是90-7.5=82.5
不知道对不对
我是这样想的

回答5:

82.5°

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