已知x^2-x-3=0,求x^4-2x^3+x的值

2024-12-29 22:53:18
推荐回答(1个)
回答1:

x^2-x-3=0
x^2-x=3

x^4-2x^3+x
=x^4-x^3+x-x^3
=x^2(x^2-x)+x-x^3
=3x^2+x-x^3
=-x^3+x^2+2x^2+x
=-x(x^2-x)+2(x^2-x)+3x
=-3x+3x+2*3
=6