一道极难的数学规律题

2025-01-25 01:52:47
推荐回答(6个)
回答1:

第六项是134.
通过观察得出,数列规律如下:(规定第n项为x(n)的话)
x(n)+x(n+2)-2*x(n-1)+1=x(n+2)+x(n+4)-2*x(n-3)
例如,x(1)+x(3)-2*x(2)+1=17+50-31*2+1=3
x(3)+x(5)-2*x(4)=50+101-74*2=3
其余项均有如上性质,故得出x(6)=134(过程不加祥写)

回答2:

130

其实有些找规律的题转弯太多,已经毫无意义了

14和74之间相差60
31和101之间相差70
那么50 和 130之间相差80正好有规律
14 31 50 74 101 X 171 215 连续的两个数相减得
17 19 24 27 X-101 171-X 44 再连续的两个数相减得
2 5 3 X-128 272 X+127
这步是5-2=3 而第三个数也是3,则:
272-(X-128)=X+127
X=136.5=137
设一个n的六次多项式,去解吧————这也是 一个规律呀!!!!!!
所以这种问题应该给一个更清晰的提示才对呀!!

回答3:

130

14和74之间相差60
31和101之间相差70
那么50 和 130之间相差80正好有规律
14 31 50 74 101 X 171 215 连续的两个数相减得
17 19 24 27 X-101 171-X 44 再连续的两个数相减得
2 5 3 X-128 272 X+127
这步是5-2=3 而第三个数也是3,则:
272-(X-128)=X+127
X=136.5=137
设一个n的六次多项式,去解吧————这也是 一个规律呀!!!!!!
所以这种问题应该给一个更清晰的提示才对呀!!

回答4:

设一个n的六次多项式,去解吧————这也是 一个规律呀!!!!!!
所以这种问题应该给一个更清晰的提示才对呀!!

回答5:

130

14和74之间相差60
31和101之间相差70
那么50 和 130之间相差80正好有规律
公务员的试题来的

回答6:

130

14和74之间相差60
31和101之间相差70
那么50 和 130之间相差80正好有规律

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