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230问答网 > 次氯酸钠通入过量二氧化碳。偏铝酸钠通入过量二氧化碳。为什么分别生成碳酸根和碳酸氢根

次氯酸钠通入过量二氧化碳。偏铝酸钠通入过量二氧化碳。为什么分别生成碳酸根和碳酸氢根

2025-03-30 22:48:10

推荐回答（2个）

回答1：

通过酸性比对

CO2 + NaClO + H2O = NaHCO3 + HClO
因为HClO的酸性介于H2CO3与HCO3-之间.
如果生成Na2CO3就会与HClO,生成HCO3-
而与偏铝酸钠反应HCO3-酸性大于偏铝酸
2 NaAlO2 + CO2 + 3 H2O = 2Al(OH)3沉淀 + Na2CO3
CO2过量：NaAlO2 + CO2 + 2 H2O = Al(OH)3 沉淀+ NaHCO3

回答2：

强酸制弱酸，酸性:碳酸＞碳酸氢根＞偏铝酸

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