高一数学,急急急。帮帮忙

2024-11-23 21:56:36
推荐回答(6个)
回答1:

sinθ与cosθ是方程 25x的平方-5(2a+1)x+a的平方+a 的两根,故两根∈[-1,1] 故有:
f(-1)>0
f(1)>0
Δ>0
-1<对称轴<1
可以解得a的取值范围
又根据根与系数关系sinθ+cosθ=? sinθ*cosθ=?
sinθ^2+cosθ^2=1 解得a的值,联系前面a的取值范围
可以知道a的值

回答2:

方程两个根的平方和=1,
x1的平方+x2的平方=(x1+x2)的平方-2×x1×x2=1

根据方程分别写出x1和x2的和与积解出a

角是锐角则x1×x2大于0,则a>0

回答3:

sinx*cosx>0
1/2sin2x>0
sin2x>0
==>
2k*pi<2x<2k*pi+pi
==>k*pik=0,1,2.....

回答4:

1)sin15°=cos75°,F(sin15°)=F(cos75°)=cos150°=
-√3/2
2)向量/AB/的模=5=√(-2-2)^2+(y+4)^2,y=
-7或者-1
3)sin(A+π/4)=1/3=sinAcosπ/4+cosAsinπ/4=√2/2(sinA+cosA)
所以,sinA+cosA=√2/3
等式同时平方,得:1+2sinAcosA=2/9
sin2A=2sinAcosA=7/9
4)f(x)为奇函数,f(-x)=-f(x)
当x<0,则-x>0,F(-X)=log2(-X)=
-log2X
令t=-x,F(t)=
-log2(-t)
所以,当X<0时,F(x)=
-log2(-x)

回答5:

当X=-b/2a=(-162)/(-1/50)=4050时,Y有最大值=-(4050^2/50)+162X4050-21000=307050
配方麻纺,所以我建议你最好用公式法....
不懂可再问,QQ:782278214
阳春2中高一生

回答6:

直接利用公式y在x
=
-(b)/
2a处取得最大值,解得x
=
4050,
再代入计算,就OK了。

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