已知(x+1)的5次方=ax的5次方+bx的4次方+cx的3次方+dx的平方+ex+f,求下列各式的值

(1)a+b+c+d+e+f(2)b+c+d+e(3)a+c+e
2024-12-14 09:36:41
推荐回答(1个)
回答1:

(x+1)^5 = x^5 + 5x^4 + 10x^3 + 10x^2 + 5x + 1

a = 1, b = 5, c = 10, d = 10, e = 5, f = 1,

a + b + c + d + e + f = (1+1)^5 = 32

b + c + d + e = 5 + 10 + 10 + 5 = 30

a + c + e = 1 + 10 + 1 = 12