已知m^2+n^2-8m-10n+41=0,求m⼀n-n⼀m的值

2024-12-11 15:29:29
推荐回答(2个)
回答1:

因为:m^2+n^2-8m-10n+41=0
所以m^2-8m+16+n^2-10n+25=0
所以(m-4)^2+(n-5)^2=0

所以m=4,n=5

所以m/n-n/m=4/5-5/4=-9/20

回答2:

m^2+n^2-8m-10n+41=0
m^2-8m+16+n^2-10n+25=0

(m-4)^2+(n-5)^2=0

m=4 n=5

m/n-n/m=-9/20