推荐回答（4个）
不是*p是首地址，而是把首地址s赋值给p了。p才是指针，不是*p，这一点要首先搞清楚！
现在让p = s;
说到这里已经很清楚了，如果还不明白，那我说s的值等于&s[0]，这下就应该明白了。
而*p是什么？*p是指针p所指内存所保存的值。既然p已经等于s，也就是等于&s[0]了，*p和s[0]又有什么不同呢？
如果还不明白，看书吧。
呵呵
*p==s[0]
p==&s[0]
都对。
*p=s[0],注意前面有个星号啊 "*",取指针指向地址的值
“*p是数组S的首地址”，这个不对，单一个p才是s首地址
p是首地址, *p是首地址指向的内容.
既然你知道p = &s[0]了, 当然*p = s[0]了. p指针, *p是对p进行取内容后的结果.
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