(1)2x-1=±3,
所以x1=2,x2=-1;
(2)(x+1)(x+2)-2(x+2)=0,
(x+2)(x+1-2)=0,
所以x1=-2,x2=1;
(3)4x2-8x+4=3,
4(x-1)2=3,
2(x-1)=±
,
3
所以x1=1+
,x2=1-
3
2
;
3
2
(4)(x+4)(x-1)=0,
所以x1=-4,x2=1;
(5)2x2-10x-3=0,
△=(-10)2-4×2×(-3)=124
x=
=10±
124
2×2
5±
31
2
所以x1=
,x2=5+
31
2
;5?
31
2
(6