数据结构C语言版,顺序线性表的合并程序。最好有注释
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#include
/*顺序表存储空间长度的最小值*/
#define LISTMINSIZE 10
/*顺序表存储结构类型定义*/
typedef struct
{
ListDT*base; /*顺序表空间基地址*/
intlistsize; /*顺序表空间尺寸*/
intlen; /*顺序表长度*/
}SeqList;
/*顺序表初始化*/
void ListInitialize(SeqList *pL, int size)
{
if(size size=LISTMINSIZE; /*限定不能小于最小尺寸*/
pL->listsize=size;
pL->base=(ListDT*)malloc(pL->listsize*sizeof(ListDT));
if(!pL->base)
exit(EXIT_FAILURE);
pL->len=0; /*初始化空表*/
}
/*按给定的下标取顺序表元素值*/
BOOL ListElem(SeqList L, int index, ListDT *pelem)
{
BOOLflg=TRUE;
if(index<0|| index>L.len-1 )
flg=FALSE; /*参数越界*/
else
*pelem=L.base[index];
returnflg;
}
/*求顺序表长度*/
int ListLen(SeqList L)
{
returnL.len;
}
/*在顺序表中指定序号位置插入元素*/
BOOL ListInsert(SeqList *pL, int pos, ListDT d)
{
BOOLflg=TRUE;
inti;
if(pos<0|| pL->len>=pL->listsize || pos>pL->len)
flg=FALSE;
else
{
for(i=pL->len-1;i>=pos; i--) /*移动数据*/
pL->base[i+1]=pL->base[i];
pL->base[pos]=d; /*写入数据*/
pL->len++; /*表长增1*/
}
returnflg;
}
/*把顺序表中指定序号的元素删除*/
BOOL ListDel(SeqList *pL, int pos)
{
BOOLflg=TRUE;
inti;
if(pos<0|| pos>=pL->len)
flg=FALSE;
else
{
for(i=pos+1;ilen; i++) /*移动数据*/
pL->base[i-1]=pL->base[i];
pL->len--; /*表长增1*/
}
returnflg;
}
/*在顺序表中查找元素*/
int ListLoc(SeqList L, ListDT d,BOOL (*equal)(ListDT,ListDT))
{
intpos=L.len-1;
while(pos>=0&& !(*equal)(L.base[pos],d))
pos--;
returnpos;
}
/*取前导元素序号位置*/
BOOL ListPrior(SeqList L, int pos, int *ppriorpos)
{
BOOLflg=TRUE;
if(pos>0&& pos *ppriorpos=pos-1;
else
flg=FALSE;
returnflg;
}
/*取后继元素序号位置*/
BOOL ListNext(SeqList L, int pos, int *pnextpos)
{
BOOLflg=TRUE;
if(pos>=0&& pos *pnextpos=pos+1;
else
flg=FALSE;
returnflg;
}
/*销毁顺序表*/
void ListDestroy(SeqList L)
{
free(L.base);
}
#endif
/*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~*/
/*
建议性测试用程序
*/
typedef enum {TRUE=1,FALSE=0} BOOL;
typedef int ListDT;
#include "seqlist.c"
void printSeqList(SeqList L)
{
inti;
ListDTx;
printf("\nList:\n");
for(i=0;i {
ListElem(L,i,&x);
printf("%3d",x);
}
}
BOOL dataequal(int x, int y)
{
return(x==y)? TRUE:FALSE;
}
#define N 5
void main()
{
inti,prior,next;
ListDTx,test[N]={10,20,30,40,50};
SeqListL;
/*初始化顺序表*/
ListInitialize(&L,N);
/*在表头插入N个元素*/
for(i=0;i ListInsert(&L,0,test[i]);
printSeqList(L);
/*删除元素*/
ListDel(&L,N/2);
printSeqList(L);
printf("\ninputa key:\n");
scanf("%d",&x);
/*查找x在表中位置*/
i=ListLoc(L,x,dataequal);
/*求x的前导元素*/
if(ListPrior(L,i,&prior))
{
ListElem(L,prior,&x);
printf("Prior:%d\n",x);
}
else
printf("noPrior.\n");
/*求x的后继*/
if(ListNext(L,i,&next))
{
ListElem(L,next,&x);
printf("Next:%d\n",x);
}
else
printf("noNext.\n");
/*求表长*/
printf("Listlength=%d",ListLen(L));
/*销毁顺序表*/
ListDestroy(L);
}
#include
#include
#include
typedef int ElemType;
const int MAXSIZE = 100;
typedef struct sqlist {
ElemType data[MAXSIZE];
int size;
}*SqList;
SqList GetEmptyList() {
SqList list = (struct sqlist *)malloc(sizeof(struct sqlist));
list->size = 0;
return list;
}
int AddElem(SqList list, ElemType x) {
int i,j;
if(list->size >= MAXSIZE) return 0;
for(i = 0; i < list->size; ++i) {
if(list->data[i] == x) return 0; // 不含等大小的元素
if(list->data[i] > x) {
for(j = list->size; j > i; --j)
list->data[j] = list->data[j - 1];
list->data[i] = x;
++list->size;
return 1;
}
}
list->data[list->size] = x;
++list->size;
return 1;
}
void ShowList(SqList list) {
int i,cnt = 0;
for(i = 0; i < list->size; ++i) {
if(i && i % 20 == 0) printf("\n"); // 每行显示20个元素
printf("%5d",list->data[i]);
}
printf("\n");
if(i % 20) printf("\n");
}
SqList MergeList(SqList La, SqList Lb) {
SqList Lc = GetEmptyList();
int i;
for(i = 0; i < La->size; ++i) // 先将La添加到Lc中
AddElem(Lc,La->data[i]);
for(i = 0; i < Lb->size; ++i) // 再将Lb添加到Lc中
AddElem(Lc,Lb->data[i]);
return Lc;
}
int main() {
SqList LA = GetEmptyList();
SqList LB = GetEmptyList();
SqList LC;
int i,N = 20;
srand((unsigned)time(NULL));
for(i = 0; i < N; ++i) {
AddElem(LA,rand()%100);
AddElem(LB,rand()%100);
}
LC = MergeList(LA,LB);
printf("LA:\n");
ShowList(LA);
printf("LB:\n");
ShowList(LB);
printf("LC:\n");
ShowList(LC);
return 0;
}
#include
typedef struct
{
int n;
int a[100];
}T;
void join(T a, T b, T *c)
{
int i, j;
c->n = 0;
for(i = 0; i < a.n && j < b.n; )
{
if(a.a[i] < b.a[j])
c->a[c->n++] = a.a[i++];
else
c->a[c->n++] = b.a[j++];
}
for(;i c->a[c->n++] = a.a[i++];
for(;j c->a[c->n++] = b.a[j++];
}
int main()
{
T a = {5, {1, 3, 5, 7, 9}};
T b = {5, {2, 4, 6, 8, 10}};
T c;
int i;
join(a, b, &c);
for(i = 0; i < c.n; i ++)
printf("%d ", c.a[i]);
printf("\n");
}
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