不定积分匧那个怎么化简的

2024-12-19 14:04:21
推荐回答(1个)
回答1:

=-1/2∫2x²/(1+x)(1-x)dx
=∫x²/(x²-1)dx
=∫1+1/(x²-1)dx
=∫1+1/2(x-1)-1/2(x+1)dx