高阶导数怎么计算 5.(3)

2024-12-14 05:48:55
推荐回答(3个)
回答1:

f(x)=sin3xcos2x=1/2[sin5x+sinx] sinx的n阶导数=sin(x+nπ/2) 【理由:(sinx)'=cosx=sin(x+π/2), (sinx)''=(sin(x+π/2))'=cos(x+π/2)=sin(x+2*π/2), 。。。以此类推】 sin5x的n阶导数=5^(n)sin(5x+nπ/2) f(x)=sin3xcos2x的n阶导数=1/2(5^(n)sin...

回答2:

5、(3)一阶导数为6(x+10)^5,二阶为6×5(x+10)^4,依次类推:
五阶为6!(x+10),所以f^5(0)=10×6!=7200
六阶为6!=720

回答3:

x=roots([1,0,1,-2,0,1,0,0,1])