(9又7分之2+7又9分之2)除以(7分之5+9分之5)=?

要求有详细的过程,要运用简便计算
2025-04-08 05:24:23
推荐回答(2个)
回答1:

(9又7分之2+7又9分之2)÷(7分之5+9分之5)

=(9+2/7+7+2/9)÷(5/7+5/9)

=(16+18/63+14/63)÷(45/63+35/63)

=(16+32/63)÷80/63

=(16+32/63)×63/80

=16×63/80+32/63×63/80

=63/5+2/5

=65/5

=13

扩展资料:

综合算式(四则运算)应当注意的地方:

1、如果只有加和减或者只有乘和除,从左往右计算,例如:2+1-1=2,先算2+1的得数,2+1的得数再减1。

2、如果一级运算和二级运算,同时有,先算二级运算

3、如果一级,二级,三级运算(即乘方、开方和对数运算)同时有,先算三级运算再算其他两级。

4、如果有括号,要先算括号里的数(不管它是什么级的,都要先算)。

5、在括号里面,也要先算三级,然后到二级、一级。

回答2:

(9又7分之2+7又9分之2)除以(7分之5+9分之5)
=(65/7+65/9)/(5/7+5/9)
=[65*(1/7+1/9)]/[5*(1/7+1/9)]
=65/5
=13.

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