如图所示的电路中,电源电压是6V,开关闭合后,电流表A1和A2的示数分别为0.2A和0.3A,则电阻R1和R2的阻值

2024-11-26 13:17:20
推荐回答(1个)
回答1:

由电路图知,两电阻并联在电源两端,
电流表A1测流过电阻R1的电流,电流表A2测干路电流;
(1)由欧姆定律得,电阻R1的阻值R1=

U
IA1
=
6V
0.2A
=30Ω;
(2)由并联电路特点知,流过电阻R2的电流
I2=IA2-IA1=0.3A-0.2A=0.1A,
由欧姆定律得,电阻R2的阻值R2=
U
I2
=
6V
0.1A
=60Ω;
答:电阻R1和R2的阻值分别为30Ω和60Ω.