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物理暑假

2025-03-14 21:33:52

推荐回答（2个）

回答1：

由平抛运动规律
（1）h-2=1/2gt1^2 x1=v1t1 t1=(0.1)^1/2s v1=0.95m/s
h=1/2gt2^2 x2=v2t1 t1=(0.5)^1/2s v2=8.5m/s
0.95m/s(2) 3x(g/2H-4)^1/2=12x(g/2H)^1/2
H=32/15m
击球高度小于32/15m不是触网就是越界

回答2：

图拍清楚

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