已知实数a,b,c满足a+b+c=-1,1⼀a+1⼀b+1⼀c=0 ,则a^2+b^2+c^2=?

2024-12-02 17:23:02
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回答1:

1/a+1/b+1/c=0
abc(1/a+1/b+1/c)=0
bc+ac+ab=0

a^2+b^2+c^2
=(a+b+c)^2-2(ab+bc+ac)
=(-1)^2-2*0
=1