√3(x²-x)-√2(x²+x)=0√3x(x-1)-√2x(x+1)=0x(√3x-√3-√2x-√2)=0x[(√3-√2)x-(√3+√2)]=0所以x1=0x2=(√3+√2)/(√3-√2) =(√3+√2)²/[(√3-√2)(√3+√2)] =(5+2√6)祝学习进步
