已知函数f(x)=sin2xcos2x-根号3sin눀2x,求f(x)在区间[0,π⼀4]上的取值范围

2024-12-31 16:14:07
推荐回答(1个)
回答1:

f*x(=1/2*sin4x-√3(1-cos4x)/2
=sin4xcosπ/3+cos4xsinπ/3-√3/2
=sin(4x+π/3)-√3/2

π/3<=4x+π/3<=4π/3
所以-√3/2<=sin(4x+π/3)<=1
在减去-√3/2
值域[-√3,1-√3/2]