已知:x²+y²-6x+2y+10=0,求x-y²的值.

2024-12-30 04:06:45
推荐回答(2个)
回答1:

x²+y²-6x+2y+9+1=0
(x-3)²+(y+1)²=0
则 x=3 y=-1

x-y²
=3-(-1)²=2

回答2:

x²+y²-6x+2y+10=0,
x²-6x+9+y²+2y+1=0,
(x-3)^2+(y+1)^2=0
x=3,y=-1
代入,3-1=2
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