用因式分解法解这个方程,3(2x-3)^2-2(2x-3)=0,要具体哦

2025-01-04 23:48:34
推荐回答(1个)
回答1:

3(2x-3)^2-2(2x-3)
=(3(2x-3)-2)(2x-3)
=(6x-11)(2x-3)
=12(x-11/6)(x-3/2)
=0
x=11/6

x=3/2