因式分解:x^2+2xy-8y^2+2x+14y-3

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2024-12-14 23:00:29
推荐回答(1个)
回答1:

x^2+2xy-8y^2+2x+14y-3
=(x-2y+3)(x+4y-1)

:x^2+2xy-8y^2=(x-2y)(x+4y)
x^2+2x-3=(x+3)(x-1)
-8y^2+14y-3=(-2y+3)(4y-1)