配方法解一元二次方程(1)2x눀-3x-5=0 (2)-2x눀-5x-3=0

2024-11-25 21:30:21
推荐回答(3个)
回答1:

(1)2x²-3x-5=0
  x^2-3/2x-5/2=0
  (x-3/4)^2=9/16+5/2=49/16
  x-3/4=±7/4
  x1=5/2 x2=-1
(2)-2x²-5x-3=0
  -2(x+5/4)^2=3-2*25/16 =-2/16
  x+5/4=±1/4
  x1=-3/2 x2=-1

回答2:

(1)2x²-3x-5=0 (2)-2x²-5x-3=0
(1)+(2)得:
-8x-8=0
x=-1

回答3:

(2X-5)(X+1)=0
X=2.5或X=-1

(2X+3)(X+1)=0
X=-1或X=-1.5