偏导数习题求高手解答

2024-12-13 08:46:27
推荐回答(2个)
回答1:

解:1。�6�8z/�6�8x=�6�8z/�6�8u × �6�8u/�6�8x × lnv + u�0�5 × �6�8z/�6�8v × �6�8v/�6�8x=6(3x-2y)ln(3x+2y) + 3(3x-2y)�0�5/(3x+2y)
�6�8z/�6�8y=�6�8z/�6�8u × �6�8u/�6�8y × lnv + u�0�5 × �6�8z/�6�8v × �6�8v/�6�8y=4(2y-3x)ln(3x+2y) + 2(3x-2y)�0�5/(3x+2y)
2。易得:lnz=cosylnsinx
�6�8z/�6�8x=cosy × cotx × (sinx)^cosy; �6�8z/�6�8y= -siny × lnsinx × (sinx)^cosy
3。�6�8z/�6�8x= -tan(x-2y);�6�8z/�6�8y=2tan(x-2y)
4。�6�8z/�6�8x=ycos(xy) - ysin(xy);�6�8z/�6�8y=xcos(xy) - xsin(xy)

回答2:

无语啊,我说不会可以嘛,唉,数学都还给老师咯