推荐回答（2个）
对于ABn型号分子，先算中心原子A周围的电子对数， 电子对数=(A的最外层电子数 +B的化合价的绝对值 *n )/2 (B是O，S，就不算电子）、电子对数=2， A原子 采取 sp杂化 2个杂化轨道 电子对数=3， A原子 采取 sp2杂化，3个 电子对数=4， A原子 采取 sp3杂化，4个CO2 电子对数= 4 /2=2 sp 杂化CH4 电子对= (4+1*4）/2=4 sp3杂化，BF3 (3+1*3)/2=3 sp2BeCl2 (2+2*1）/2=2 sp烃不属于ABn型 ，不能用直接用上述方法判断C2H4 这个 分子中含有C=C， Ｃ采取sp2杂化C6H6 凯库勒式中也含有Ｃ=Ｃ，Ｃ采取sp2杂化
记住物质的 空间构型 基本 直线型的 SP1 平面性的 SP2 空间三角锥 SP3其实 这个问题理解起来很难 基本就是 蛋鸡问题问你 为什么 SP1杂化 回答说因为空间构型直线型问你 为什么 直线型 回答 SP1 杂化至于杂化数目 大约记点 最外层电子数 还有 基本的常识 就行了
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