解y=2sin(π/3-2x) =2sin[-(2x-π/3)] =-2sin(2x-π/3) 要求y=2sin(π/3-2x)的单调增区间只需求sin(2x-π/3)的单调减区间即可 当π/2+2kπ<=2x-π/3<=3π/2+2kπ即5π/12+kπ<=x<=11π/12+kπ时sin(2x-π/3)是减函数∴y=2sin(π/3-2x)的增区间为[5π/12+kπ，11π/12+kπ]
