观察下列等式的变形规律2⼀(1×3)=1-(1⼀3),2⼀(2×4)=1⼀2-1⼀4,2⼀3×5=1⼀3-1⼀5,...请解答下列问题;

2024-12-28 07:23:41
推荐回答(1个)
回答1:

解:(1)2/n(n+2)=1/n-1/(n+2)
(2)1/n-1/(n+2)=(n+2-n)/n(n+2)=2/n(n+2)
(3)设和为S,则2s=[2/(1*3)+2/(3*5)+...+2/(49*51)]+[2/(2*4)+2/(4*6)+...+2/(48*50)
=(1-1/3+1/3-1/5+...+1/49-1/51)+(1/2-1/4+1/4-1/6+...+1/48-1/50)
=1-1/51+1/2-1/50
=1862/1275
∶原式=931/1275