若x^2-3x-2009=0,求代数式1-x^2+(x-1)^3⼀x-1的值

2024-12-28 07:34:22
推荐回答(1个)
回答1:

[1-x^2+(x-1)^3]/x-1
=[-(x-1)(x+1)+(x-1)³]/(x-1)
=[(x-1)(-x-1+x²-2x+1)]/(x-1)
=x²-3x
=x²-3x-2009+2009
=2009