(2x-3)/(x-1)(x+1)=(A+x)/(x-1)+B/2将等式两边同乘以(x-1)(x+1)2x-3=(A+x)(x+1)+B/2(x�0�5-1）2x-3=x�0�5+(A+1)x+A+﹙B/2﹚x�0�5-B/2A+1=2 A-﹙B/2﹚=-3 1+B/2=0这样解不出来。你的题目让人不能理解，总之将等式两边同乘以一个数去掉分母，再根据同类项求出A,B
