你好：
(x^2-1)/(x+1)=0
(x+1)(x-1)/(x+1)=0
x-1=0
x=1
选d
（m^2-16）/(3m-12)
=(m+4)(m-4)/3(m-4)
=(m+4)/3
m=-1,
=(-1+4)/3
=1
(x^2-2xy+y^2-1)/(x-y-1)
=[(x-y)^2-1]/(x-y-1)
=(x-y-1)(x-y+1)/(x-y-1)
=x-y+1
(a/b)*(b/a^2)
=a*b/（b*a^2）
=1/a
(x+2)/(x-3)*(x^2-6x+9)/(x^2-4)
=[(x+2)/(x-3)]*(x-3)^2/(x+2)(x-2)
=(x-3)/((x-2)
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