4x-16x대,(-3分之1)的-2次方+(9分之1)的0次方+(-5)대÷(-5)눀

2024-12-15 14:25:51
推荐回答(1个)
回答1:

4x-16x³
=4x(1-4x²)
=4x(1-2x)(1+2x)

(-1/3)^-2+(1/9)^0+(-5)^3÷(-5)^2
=9+1+(-5)^1
=10-5
=5