9(x-3)^2=4(x-2)^2 用因式分解法解方程

2024-11-25 03:38:51
推荐回答(2个)
回答1:

9(x-3)²=4(x-2)²

9(x-3)²-4(x-2)²=0
[3(x-3)-2(x-2)]*[3(x-3)+2(x-2)]=0
(x-5)(5x-13)=0
x1=5,x2=13/5

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回答2:

9(x-3)^2=4(x-2)^2
9x^2-54x+81-4x^2+16x-16=0
5x^2-38x+65=0
(5x-13)(x-5)=0
(5x-13)=0
x=13/5
(x-5)=0
x=5