化简函数f(x)=sin2x+根号3(cos2x+1)-根号3 =sin2x+根号3cos2x =2sin(2x+π/3)即最小正周期为π2x+π/3属于-π/2+2kπ到π/2+2kπ递增,解出,x属于-5/12π+kπ到1/12π+kπ递增