先化简,再求值:x^2-5x+6⼀3x^2-3x÷(1-3⼀x+1)(1+2⼀x-3),其中x=2.

2024-12-26 02:12:29
推荐回答(1个)
回答1:

你好,你的题目表达不清,下面我按照最可能表达的题意解题。

解:
(x^2-5x+6)/(3x^2-3x)÷{[1-3/(x+1)][1+(2/x-3)]}
=(x-2)(x-3)/3x(x-3)÷{[(x-2)/(x+1)][(x-1)/(x-3)]}
=(x-2)(x+1)(x-3)/[3x(x-2)(x-1)]
=(x+1)(x-3)/[3x(x-1)]
=(2+1)(2-3)/[3×2(2-1)]
=3×(-1)/6
= -1/2