(1)用含字母的式子表示这种数量关系;
1/[N*(N+1)]=1/N-1/(N+1)
2)计算1/1*2+1/2*3+1/3*4+……+1/49*50
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+......+(1/49-1/50)
=1-1/50
=49/50
1/n×(n+1)=1/n-1/(n+1)
原式=1-1/2+1/2-1/3+……+1/49-1/50
=1-1/50
=49/50
(1)1/a*(a+1)=1/a-1/(a+1)
(2)原式=1-1/2+1/2-1/3+1/3-1/4+....+1/49-1/50=1-1/50=49/50
(1) 1/[n×(n+1)]=1/n - 1/(n+1)
(2)1/1*2+1/2*3+1/3*4+……+1/49*50
=(1-1/2)+(1/2-1/3)+……+(1/49-1/50)
=1-1/50
=49/50