计算(x的4次方+1)(x的2次方+1)(x-1)

2025-01-07 00:42:59
推荐回答(3个)
回答1:

先乘以(x+1)后与(x-1)构成平方差公式以此类推后再除以(x+1)

回答2:

(x的4次方+1)(x的2次方+1)(x-1)
=(x^4+1)(x^2+1)(x-1)
=(x^6+x^4+x^2+1)(x-1)
再相乘

回答3:

x7-x6+x5-x4+x3-x2+x-1