分解因式:(6x-1)(2x-1)(3x-1)(x-1)+xx

过程
2024-12-29 20:59:22
推荐回答(5个)
回答1:

(6x-1)(2x-1)(3x-1)(x-1)+xx
=(6x-1)(x-1)*[(2x-1)(3x-1)]+x^2
=(6x^2-7x+1)*(6x^2-5x+1)+x^2
设t=6x^2-6x+1
上式化为(t-x)(t+x)+x^2=t^2=(6x^2-6x+1)^2
6x^2-6x+1已经不能再分解了~~

回答2:

j

回答3:

(6x-1)(2x-1)(3x-1)(x-1)+x^2
=[(6x-1)(x-1)][(2x-1)(3x-1)]+x^2
=(6x^2-7x+1)(6x^2-5x+1)+x^2
=(6x^2-6x+1)^2

回答4:

(6x-1)(2x-1)(3x-1)(x-1)+x^2
=[(6x-1)(x-1)][(2x-1)(3x-1)]+x^2
=[(6x^2+1)-7x][(6x^2+1)-5x]+x^2
=(6x^2+1)^2-12x(6x^2+1)+35x^2+x^2
=(6x^2+1)^2-12x(6x^2+1)+36x^2
=(6x^2+1)^2-2*(6x)*(6x^2+1)+(6x)^2
=(6x^2-6x+1)^2

回答5:

(6x-1)(2x-1)(3x-1)(x-1)+xx
=(12x^2-8x+1)(3x^2-4x+1)+x^2
=36x^4-48x^3+12x^2-24x^3+32x^2-8x+3x^2-4x+1+x^2
=36x^4-72x^3+48x^2-12x+1