:[x^2+y^2)-(x-y)^2+2y(x-y)]÷4y=(x²+y²-x²+2xy-y²+2xy-2y²)÷4y=(4xy-2y²)÷4y=(2x-y)÷2=4²÷2=8∴代数式值的立方根=³√8=2