已知X+Y=3,XY=-12,求下列各式的值,①X^2+Y^2②X^2-XY+Y^2 求数学高手的帮忙,谢谢!

2024-12-25 02:25:47
推荐回答(2个)
回答1:

1、x²+y²
=(x+y)²-2xy
=3²-2x(-12)
=33

2、x²-xy+y²
=(x+y)²-3xy
=3²-3x(-12)
=45

回答2:

,①X^2+Y^2
=(x+y)²-2xy
=3²-2×(-12)
=33
②X^2-XY+Y^2
=33-(-12)
=45