求解计算机网络的一道计算题!!

2024-11-26 20:14:30
推荐回答(3个)
回答1:

把每个目的地址和每个子网掩码相与,看与那个目的地址相同就是从那个端口发出去,下一跳就是后面对应的。比如172.16.0.1可以表示成2进制 10101100.00010000.00000000.00000001。分别与几个子网掩码相与

回答2:

224是掩码的最后一位转化为2进制是11100000即有3位为1,2^3=8可以划分为8个子网,有5位为0,2^5-2=30每个子网有30台主机,用256-224=32,子网的块大小为32,即子网分别为0,32,64,96,128,160,192,224子网,子网的首位不能使用,所以主机地址需要用32-2.

回答3:

172.16.0.1、loopback 本地
172.16.112.10、1.1.1.3
172.16.36.57、1.1.1.1
172.16.0.255、广播地址,本网段内广播
172.16.64.38 1.1.1.4

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