求不定积分∫tan^6xsec^4xdx

2024-12-14 06:32:47
推荐回答(1个)
回答1:

∫ tan^6xsec^4x dx
= ∫ tan^6xsec^2x d(tanx)
= ∫ tan^6x(1 + tan^2x) d(tanx)
= ∫ (tan^6x + tan^8x) d(tanx)
= (1/7)tan^7x + (1/9)tan^9x + C