计算:(1+1⼀1×3)×(1+1⼀2×4)×(1+1⼀3×5)×(1+1⼀4×6)×.....×(1+1⼀11×13)

2024-12-16 01:26:14
推荐回答(4个)
回答1:

(1+1/1×3)*(1+1/2×4)*(1+1/3×5)*(1+1/4*6)……(1+1/11*13)=(1+1×3)*(1+2×4)*(1+3×5)*(1+4*6)……(1+11*13)/[1×2×3²×4²×.....×11²×12×13)]=(2²×3²×4²×5²×......×11²×12²)/[1×2×3²×4²×.....×11²×12×13)]=2×12/13=24/13

回答2:

把一加上去后前一项的分子都是后一项分母的两倍
所以原式=2的十次方乘以二十四=1024乘以24=24576

回答3:

(2^2/1*3)*(3^2/2*4)*(4^2/3*5)*.......*(12^2/11*13)
=2*12/13
=24/13
很高兴为您解答,不明白可以追问。望采纳~

回答4:

(1+1/x+(x+2))