∫x(x^2-1)dx⼀(x^4+1)的不定积分,求教!

2024-12-22 19:29:01
推荐回答(2个)
回答1:

∫x(x^2-1)dx/(x^4+1)

=∫x^3dx/(x^4+1)-∫xdx/(x^4+1)
=1/4∫1/(x^4+1)dx^4-1/2∫1/(x^4+1)dx^2
=1/4ln(x^4+1)-1/2arctan(x^2)+C

回答2:

∫x(x^2-1)dx/(x^4+1)
=∫(x^3-x)dx/(x^4+1)
=∫x^3dx/(x^4+1)-∫xdx/(x^4+1)
=1/4∫d(x^4+1)/(x^4+1)-1/2∫dx^2/(x^4+1)
=ln(x^4+1) /4 -arctanx^2 /2 +C