∫(0,π⼀2)(-sinx+cosx)⼀(sinx+cosx)dx 请用换元法求出定积分

2024-12-14 19:38:37
推荐回答(1个)
回答1:

∫[0,π/2](-sinx+cosx)/(sinx+cosx)dx

=∫[0,π/2]1 /(sinx+cosx)d(sinx+cosx)
=ln(sinx+cosx)[0,π/2]
=0