数据结构学生运动会成绩管理

2025-03-02 16:59:22
推荐回答(3个)
回答1:

#include
#include
#include
#include
int a,b,c,d,i,j; 
 
struct node 
 

  int num; 
}; 
 
struct node *f[22];
 
void exit0()                   /*创建文档*/    

      FILE *fp; 
      int k; 
      alp:if((fp=fopen("sore.txt","w"))==NULL)
 

      printf("创建文件失败\n");
      printf(" 1*****重试\n");
      printf(" 2*****强制退出(数据将不会保存到文件)\n");       
      printf(" 3*****回到主菜单\n");
      alj: scanf("%d",&k); 
 
      if(k==1) 
           goto alp; 
      else if(k==2) 
           exit(0); 
      else if(k==3) 
           return; 
      else 
 

      printf("输入错误,请重新输入:");
      goto alj; 

 

      fprintf(fp,"\n\n"); 
      fprintf(fp,"运动会分数统计表\n\n\n");
      fprintf(fp,"项目代号");
for(i=1;i<=c+d;i++)
      fprintf(fp,"%5d",i); 
      fprintf(fp," "); 
      fprintf(fp,"\n 学院代号\n");
for(i=1;i<=a;i++) 
 

      fprintf(fp,"%10d",i); 
for(b=1;b<=c+d;b++)

      fprintf(fp,"%5d",f[i][b].num); 

      fprintf(fp,"\n"); 

 
      fprintf(fp,"\n\n"); 
      fprintf(fp," 注:本次运动会有%d个学校参赛\n\n",a);
      fprintf(fp," 其中1 ~%d组是男子组,%d~ %d组是女子组\n",c,c+1,c+d);
      printf("\n比赛成绩已保存到当前路径下的sore.txt文件中\n\n");
      fclose(fp); 
      exit(1); 
 

 
int choose()                     /*菜单选择函数*/
 

 
int choo; 
 
    printf("\t\t                运动会分数统计               \n");   
    printf("\t\t* * * * * * * * * * * * ** * * * * * * * * *\n");   
    printf("\t\t                                             \n");   
    printf("\t\t* * * * * * * * * * * * ** * * * * * * * * *\n");   
    printf("\t\t*         1.输入各个项目成绩并存储文件      *\n");   
    printf("\t\t*         2.统计各学校总分                  *\n");   
    printf("\t\t*         3.按学校编号排序输出              *\n");   
    printf("\t\t*         4.按学校总分排序输出              *\n");   
    printf("\t\t*         5.按男团体总分排序输出            *\n");   
    printf("\t\t*         6.按女团体总分排序输出            *\n");   
    printf("\t\t*         7.按学校编号查询学校某个项目情况  *\n");  
    printf("\t\t*         8.按项目编号查询取得名次的学校    *\n");   
    printf("\t\t*         9.退出                            *\n");   
    printf("\t\t* * * * * * * * * * * * ** * * * * * * * * *\n");   
    printf("\t\t          请选择(1-9):");  
 
      scanf("%d",&choo); 
    return(choo-1); 
 

                      
void input()                /* 输入各个项目成绩并存储数据*/  
 

 
intab,ac,ae,af,g=1,get[5]={0,0,0,0,0}; 
      printf("\n请输入项目代号:");
      ale:scanf("%d",&ab); 
if(ab>c+d||ab<1)
 

      printf("\n此项目代号不存在,重新输入\n");
      goto ale; 

 
ae=0; 
 
for(i=0;i<=a;i++) 
 

      if(f[i][ab].num!=0) 
 

      ae=1; 
      break; 

 

      if(ae==1) 

 
      al2: printf("\n此项目成绩曾经已被录入过,是否要重新录入(您输入的项目代号可能有误,强烈建议您查证后再录入):\n");
      printf(" 1++++重新录入(若重新录入,以前的该项目成绩将被删除)\n");
      printf(" 2++++不要,待查证后再录入\n\n");
      scanf("%d",&af); 
if(af==2) 

      printf("您已取消录入!!!!!\n");
      return; 

else if(af==1) 

      for(i=1;i<=a;i++) 

           if(f[i][ab].num!=0) 

                 f[i][0].num=f[i][0].num-f[i][ab].num;
                 if(ab<=c) 
                      f[i][c+d+1].num=f[i][c+d+1].num-f[i][ab].num;
                 else 
                      f[i][c+d+2].num=f[i][c+d+2].num-f[i][ab].num;

                      f[i][ab].num=0; 


           else 
                 goto al2; 

           al: printf("\n此项目是以前几名为胜出者:\n\n");
           printf(" 3-------以前三名\n");
            printf("5-------以前五名\n\n");
           scanf("%d",&ac); 
      if(ac==3) 

           printf("\n请依次输入获胜学院代号:");
           af=5; 
           for(i=0;i<3;i++) 

                 alq:scanf("%d",&ae); 
                 if(ae>a||ae<1) 

                      printf("%d学院代号不存在,重新输入第%d名的学院代号\n",ae,g);
                      goto alq; 

                      for(b=0;b<5;b++) 

                      if(ae==get[b]) 
{                     printf("同一个学院不能在同一项目中有两个名次,请重新输入第%d名的学院代号!!!\n",g);
                      goto alq; 

                      else 
                            get[b]=ae; 
      } 
                 f[ae][0].num=f[ae][0].num+af; 
                 f[ae][ab].num=af; 
                 if(ab<=c) 
                      f[ae][c+d+1].num=f[ae][c+d+1].num+af;
                 else 
                      f[ae][c+d+2].num=f[ae][c+d+2].num+af;
                      if(af>3) 
                            af=af-2; 
                      else 
                            af--; 
                            g++; 


           else if(ac==5) 

                 printf("请依次输入获胜学院代号:");
                 af=7; 
                 for(i=0;i<5;i++) 
 

           alw: scanf("%d",&ae); 
           if(ae>a||ae<1) 

                 printf("%d学院代号不存在,重新输入第%d名的学校代号\n",ae,g);
                 goto alw; 

           for(b=0;b<5;b++) 

                 if(ae==get[b]) 

                 printf("同一个学院不能在同一项目中有两个名次,请重新输入第%d名的学校代号!!!\n",g);
                 goto alw; 

                 else 
                 get[b]=ae; 

      f[ae][0].num=f[ae][0].num+af; 
      f[ae][ab].num=af; 
      if(ab<=c) 
           f[ae][c+d+1].num=f[ae][c+d+1].num+af;
      else 
           f[ae][c+d+2].num=f[ae][c+d+2].num+af;
      if(af>3) 
           af=af-2; 
      else 
           af--; 
           g++; 


      else 
      goto al; 
      printf("\n\n 输入完成 ! !! ! \n"); 

 
void each()                        /* 输出各学校总分 */   

      printf("\n 对应的格式为:\n学院代号:团体总成绩\n\n"); 
      for(i=1;i<=a;i++) 

           printf("%2d:%3d",i,f[i][0].num); 
           if(i%3==0) 
                 printf("\n "); 


 
void biaohao()                 

      printf("\n项目代号"); 
      for(i=1;i<=c+d;i++) 

      if(i>9) 
           printf("%4d ",i); 
      else 
           printf("%5d ",i); 

      printf("\n"); 
      printf("学院代号\n"); 
      for(i=1;i<=a;i++) 

           printf(" \t%d ",i); 
      for(b=1;b<=c+d;b++) 

           if(f[i][b].num>9) 
                 printf("%4d",f[i][b].num);
           else 
                 printf("%5d",f[i][b].num);

           printf("\n"); 


 
void zongfen() 
 

      struct nod 

      int ke; 
      int num; 
}; 
 
      int ha; 
      struct nod *de; 
      de=(struct nod *)malloc(sizeof(structnod)*a+1);
      printf("\n 按学校编号排序输出\n\n");
      printf("\t学院代号总分\n\n");
 
      for(i=1;i<=a;i++) 

      de[i].ke=i; 
           de[i].num=f[i][0].num; 

      for(i=1;i<=a;i++) 

      for(b=i;b<=a;b++)

 
      if(de[b].num>de[i].num) 

      ha=de[b].ke; 
      de[b].ke=de[i].ke; 
      de[i].ke=ha; 
      ha=de[b].num; 
      de[b].num=de[i].num; 
      de[i].num=ha; 
 



      for(i=1;i<=a;i++) 

           printf("%12d%8d\n",de[i].ke,de[i].num);

}
 
void nanzong() 
 

struct nod 

      int ke; 
      int num; 
}; 
 
      int ha; 
      struct nod *de; 
      de=(struct nod *)malloc(sizeof(structnod)*a+1); 
      printf("\n 按男子团体总分排序输出\n\n");
      printf(" \t学院代号男子团体总分\n\n");
      for(i=1;i<=a;i++) 

           de[i].ke=i; 
           de[i].num=f[i][c+d+1].num; 

      for(i=1;i<=a;i++) 

      for(b=i;b<=a;b++)

           if(de[b].num>de[i].num) 

           ha=de[b].ke; 
           de[b].ke=de[i].ke; 
           de[i].ke=ha; 
           ha=de[b].num; 
           de[b].num=de[i].num; 
           de[i].num=ha; 



      for(i=1;i<=a;i++) 

           printf("%13d%12d\n",de[i].ke,de[i].num);


 
void nvzong() 
 

struct nod 

      int ke; 
      int num; 
}; 
 
      int ha; 
      struct nod *de; 
      de=(struct nod *)malloc(sizeof(structnod)*a+1); 
      printf(" 按女子团体总分排序输出\n\n");
      printf(" \t学院代号女子团体总分\n\n");
      for(i=1;i<=a;i++) 

           de[i].ke=i; 
            de[i].num=f[i][c+d+2].num;

      for(i=1;i<=a;i++) 

      for(b=i;b<=a;b++)

           if(de[b].num>de[i].num) 

                 ha=de[b].ke; 
                 de[b].ke=de[i].ke; 
                 de[i].ke=ha; 
                 ha=de[b].num; 
                 de[b].num=de[i].num; 
                 de[i].num=ha; 



      for(i=1;i<=a;i++) 

           printf("%15d%13d\n",de[i].ke,de[i].num);


 
void xuexiao() 

      int dr,dt; 
      printf("\n请输入您要查询的学院代号:");
      aly:scanf("%d",&dr); 
      if(dr>a||dr<1) 

      printf("学院代号不存在,重新输入\n");
      goto aly; 

      printf("请输入您要查询的项目代号:");
      alo:scanf("%d",&dt); 
      if(dt>c+d||dt<1) 

      printf("项目代号不存在,重新输入\n");
      goto alo; 

      printf("\n\n %3d 学院的%3d 项目成绩为%3d\n",dr,dt,f[dr][dt].num);

 
void xiangmu() 

      int ge,sedy=0; 
      printf("\n 请输入您要查询的项目代号:");
      all:scanf("%d",&ge); 
      printf("\n");
 
      if(ge>c+d||ge<1)
 
{
      printf("没有此项目代号,重新输入\n");
      goto all; 

      for(i=1;i<=a;i++) 

           if(f[b][ge].num==2) 
                 sedy=1; 
 

 
           if(sedy==0) 
 

 
           printf("此项目没有录入成绩\n");
 
           return; 
 

 
      for(i=1;i<=a;i++) 
 

           if(f[i][ge].num==7) 

 
                 printf(" 此项目取前5名获奖者\n");
                 break; 
 

 

 
                 if(i==a+1) 
                      printf(" 此项目取前3名获奖者\n");
                      printf("\n 获胜名单由成绩高到低依次为:\n\n"); 
                 for(i=7;i>0;i--) 
 

                 for(b=1;b<=a;b++) 

 
                      if(f[b][ge].num==i) 
                            printf("%5d",b);



 
void(*g[])()={input,each,biaohao,zongfen,nanzong,nvzong,xuexiao,xiangmu,exit0};
 
void main() 
 

      int choos; 
      printf("\n\n * * * 运动会分数统计* * *\n\n\n"); 
      printf("共有多少个学院参赛:");
      scanf("%d",&a); 
      while(a<=0||a>20) 

           if(a<=0) 

                 printf("\n 参赛学院个数不能是负数或零\n\n");
                 printf("共有多少个学院参赛:");
                 scanf("%d",&a); 

      if(a>20) 
 

      printf("\n 参赛学院个数不能大于20\n\n");
      printf("共有多少个学院参赛:");
      scanf("%d",&a); 


      printf("有几个男子组:");
      scanf("%d",&c); 
      printf("有几个女子组:");
      scanf("%d",&d); 
      for(i=0;i<=a;i++) 
      { 
           f[i]=(struct node*)malloc(sizeof(struct node)*(c+d+3)); 
                 for(j=0;j<=c+d+2;j++) 
                      f[i][j].num=0; 

                 choos=choose(); 
      while(1) 
      { 
           while(choos<0||choos>8) 
                      choos=choose(); 
                      (*g[choos])(); 
                      printf("\n");
                      choos=choose(); 

}

回答2:

晕这个你可以自己去做啊,不是有办公软件吗?这个太简单了~~和我联系912549388

回答3:

看到这种问题真的很无语,谁会为你花上几天时间来写这样的程序呢?

你自己怎么没有去做?为什么老想着不劳而获呢? 同学,你这样是永远也不会进步的。

如果你去做了,问的是一个技术细节,我相信很多人都愿意帮助你的。

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