求不定积分∫x⼀(1+2x^4)dx 谢谢!

2024-12-16 12:07:04
推荐回答(1个)
回答1:

不定积分∫x/(1+2x^4)dx
=1/2∫2x/(1+2x^4)dx
=1/2∫1/(1+2x^4)dx^2
=1/4∫1/(1/2+x^4)dx^2
=(2^(1/2)*atan(2^(1/2)*x^2))/4+C