＜x²-2x＞+＜x²-2x＞-2=0怎么解解：＜x²-2x＞+＜x²-2x＞-2=02x²-4x-2=0x²-2x-1=0（x-1）²=2x-1=±√2x=√2+1 或 x= 1-√2
＜x²-2x＞+＜x²-2x＞-2=02＜x²-2x＞-2=0x²-2x-1=0x²-2x+1=2(x-1)²=2x=1±√2
