(1+x)/(1-x)>0(1+x)(1-x)>0(x+1)(x-1)<0-1y=log(a,(1+x)/(1-x))=log(a,1+x)-log(a,1-x)当a>1在-1log(a,1+x)递增log(a,1-x)递减-log(a,1-x)递增y=log(a,1+x)-log(a,1-x)递增当0log(a,1+x)递减log(a,1-x)递增-log(a,1-x)递减y=log(a,1+x)-log(a,1-x)递减
