初二数学题,求高手速解!!要有详细过程!!下午两点之前一定要啊!!

2024-11-25 14:58:00
推荐回答(4个)
回答1:

依题意(1/2+π/3)x+(1/3+π/2)y=4+π
(1/2+π/3)x+(1/3+π/2)y=(1/2x+1/3y)+(π/3*x+π/2×y)==(1/2x+1/3y)+π*(x/3+y/2)
所以1/2x+1/3y=4
x/3+y/2=1
解得x=12,y=-6
所以-x-y=-12-(-6)=-6

回答2:

解:由(1/2+π/3)x+(1/3+π/2)y-4-π=0得:
x/2+πx/3+y/3+πy/2-4-π=0
(x/2+y/3)+(πx/3+πy/2)=4+π即:
x/2+y/3=4(1式)
πx/3+ay/2=π
即:x/3+y/2=1(2式)(a不等于0)
(1式)*12得:
6x+4y=48(3式)
(2式)*18得:
6x+9y=18(4式)
(3式)-(4式)
-5y=30
y=-6
x=12
-x-y=-12-(-6)=-6

回答3:

整理得:(x/2+y/3)+pi(x/3+y/2)=4+pi【pi为π】
所以:x/2+y/3=4
x/3+y/2=1
解得:x=12 y= -6

回答4:

e